If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2a^2-43a+228=0
a = 2; b = -43; c = +228;
Δ = b2-4ac
Δ = -432-4·2·228
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-5}{2*2}=\frac{38}{4} =9+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+5}{2*2}=\frac{48}{4} =12 $
| 3.2x-17.88=x+30 | | 2x+3(-7x-6)=115 | | 3.2d-17.88=d+30 | | -3.6+6.1=6x-2.6-5x | | 3x-5(x-5)=-9+2x+2 | | 2(4-(-5x-2)=30x+20 | | 9/2g=3/5 | | 6x+7=8x-1; | | x=3x^2-15x | | 2n-3=3n+3 | | 18x+252=4 | | 3x-6x(6+8)=7(7+3) | | 3x+4-x=4x-5 | | x-2x+8/3=1/4(x-2-x)-3 | | 6/4+2x=-2/x-10 | | 420÷d=30;d=15 | | 1/3x+1x=8 | | 7x+2(6x+15)=201 | | 2x+20=4÷7x | | 2=k4 | | 2=k1 | | (39/5)=2m | | -5=10-3n | | 90=2x+(4x-12) | | x-2x+8/3=1/4(x-2-x)/6-3 | | Z÷4+4=7-z÷4 | | 15x+2/16=0 | | -8x+14=-2(4x-7 | | (100-x)^2=0 | | 3/6z=6 | | -1(1/2)+v=-3(3/10) | | 3x+7=1+9x |